i would need the day of month {ddz} befor and after.
today is 16 … i would need yesterday and tomorrow => 15 and 17
anyone an idea how to handle that?
Yesterday (considers leap year and previous month when today is 1 - test with date st Mar 2028 for next leap year)
{dd} > 1 and {dd} - 1 or ({dn} - 1) == 2 and ({dyy} % 4 == 0 and 29 or 28) or ({dn} - 1) == 4 and 30 or ({dn} - 1) == 6 and 30 or ({dn} - 1) == 9 and 30 or ({dn} - 1) == 11 and 30 or 31
Tomorrow
{dd} < {ddim} and {dd} + 1 or 1
If yesterday can be simplified, please post revision
If you set preview day to 1st of month, that formula will return “0”.
Never ever this will work. Subtract 1 from 31 march and maybe it’s leap year…
I tried lua, but it doesn’t work on every watch… In Studio it shows correct value but not on watch. That’s why i asked.
=>
Yesterday:
tonumber(os.date(“%d”, os.time() - 86400))
Tomorrow:
tonumber(os.date(“%d”, os.time() + 86400))
My solution works on Samsung?
Great!